CERN
brochures:
Information
booklet for teachers
WG
Leader: Antonella del Rosso
LHC
and educational activity
The
Large Hadron Collider (LHC) is a particle accelerator. This accelerator is being
built in CERN. Hopefully it will work in 2006. This new accelerator will be
installed into the same tunnel as the Large Electron-Positron collider operated
before. The circular underground tunnel is 27 km long. Two proton beams will be
accelerated to 7 TeV in the opposite directions to collide with each other.
Superconducting magnets keep the proton beams on track. Four huge detectors will
be built to detect the collision events.
A
possible activity for the theme LHC:
The aim
of the activity is:
·
to practice the concept of the electronvolt (eV),
·
to determine the collision energy of two accelerated protons in the LHC,
·
to point out, that this energy is not too large,
·
to determine the velocity of some macroscopic object, whose energy is the
same,
·
to determine the volume of a proton and a chosen macroscopic object,
·
to determine the energy volume density in both cases,
·
to take the ratio of the two energy densities, and discuss the obtained
result,
·
to show how large number is it, using an example with linear dimension
To
practice the concept of the electronvolt (eV):
·
If a charge Q passes through a potential difference U the work done by
the field on the charge is W = Q U
·
If the charge is just an electron Q = 1.6 10- 19 C, and the
potential difference is U = 1 V, then the work is W = Q U = 1.6 10-19
J.
To determine the collision energy of two accelerated protons in the LHC:
·
Determine the energy of the collision, if both proton is accelerated to 7
TeV, that is E = 14 TeV
·
1 keV = 103 eV
·
1 MeV = 106 eV
·
1 GeV = 109 eV
·
1 TeV = 1012 eV
·
E = 14 TeV = 14 1012 1.6 10-19 = 2.24 10-6
J
To point out, that this energy is not
too large:
·
This energy is not too large, precisely saying it is very very small if
this energy is possessed by a macroscopic object
To determine the velocity of some macroscopic object, whose energy is the same:
·
Consider four different macroscopic objects with masses
·
Dust m0 = 10-6 kg
·
Fly m1 = 10-3 kg
·
Small block m3 = 1 kg
·
Car m4 = 103 kg
·
So one object has the half of the energy above Ehalf = 1.12 10-6
J
·
We can apply the classical kinetic energy formula, as
, and solving the equation for vi we can obtain
.
·
For the different macroscopic object the velocities respectively are:
·
Dust v0 = 1.5 m/s
·
Fly v1 = 4.73 10-2 m/s
·
Small block v2 = 1.5 10-3 m/s
·
Car v3 = 4.73 10-5 m/s
To determine the volume of a proton and a chosen macroscopic object:
·
As we know the radius of a proton is rp ~ 0.7 10-15
m, so its volume is
, that is Vp = 1.44 10-45 m3.
·
Choose the macroscopic object to be this slowly flying fat fly, whose
dimensions are 3 mm x 3 mm x 5 mm, that is its volume is V1 = 4.5 10-8
m3.
To determine the energy volume density in both cases:
·
Now we can already determine the energy volume density in the place of
the collision, in both cases:
·
In case of the proton
, that is rp
= 7.78 1038 J/m3.
·
In case of the slowly flying fly r1
= 2.49 101 J/m3.
·
So we have already got the answer for the question, why the LHC is being
built!!!
To take the ratio of the two energy
densities, and discuss the obtained result:
·
Take the ratio of the two energy densities as
, inserted the numerical values the result: n »
3 1037.
·
This is a huge number. So we can understand that the energy produced by
the Large Hadron Collider is very small, but it is concentrated into the very
tiny space, where the two protons collide.
·
Some part of this energy will be materialized
( E = m c2 ).
To show how large number is it, using
an example with linear dimension:
·
A man could not imagine a number which is greater than 1 million that is
106.
·
To imagine such a huge number, a comparison would be helpful.
·
Consider first the size of the known universe, it is about 1026
m, and the size of an atom, is about 10-10 m, and compare them, that
is take their ratio.
·
The obtained number is only 1036, one can see that it is only
the tenth part of the huge number above.