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Bubble Chamber Relativity    

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If we assume that that we have 1 (one) missing particle X, we now know that the energy of the particle is

EX= 3.53939 GeV

In order to identify the particle X, we have to calculate its mass.

To do that we will use the energy-relation

E2 = p2 c2 + m2 c4

We have already calculated Ex, and we can find the momentum px.

of the particle, because momentum must be conserved in all processes.

We can then calculate the mass from the expression

 

Now, we have to calculate px, and then px2, using momentum conservation.

Because the momentum conservation law is a vector law, we can apply the law in x-, y- and z-directions separately. 

From the tables we get (in momentum units GeV/c):

px (X) = px (K-) - px (p) - px (p-)

px (X) = 8.26131 - 0.32426 - 4.49326 = 3.44309

 

and,

 

py (X) = - 0.15642 - (-0.45360) - 0.73621 = -0.43903

pz (X) = 0.01320 - 0.04282 - (-0.51122) = 0.48160

 

This gives us for the X-particle p = 3.50421 GeV/c

 

From the calculated values of energy and momentum, expression (2) gives us mX = 497.8 MeV/c2.

 Using the particle table you now can identify the neutral particle.

 


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Last modified: 25 July 2001